7x^2+96X-192=0

Solution for 7x^2+96X-192=0 equation:

7x^2+96x-192=0

a = 7; b = 96; c = -192;
Δ = b2-4ac
Δ = 962-4·7·(-192)
Δ = 14592
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{14592}=\sqrt{256*57}=\sqrt{256}*\sqrt{57}=16\sqrt{57}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(96)-16\sqrt{57}}{2*7}=\frac{-96-16\sqrt{57}}{14}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(96)+16\sqrt{57}}{2*7}=\frac{-96+16\sqrt{57}}{14}
$